
Xemnas
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Posts: 1987
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A little help
Posted: Jul 12, 2011, 20:34:30
Hey guys, I'm going to be taking my ASVAB test next week, And i wrote down a few notes during my Pre-test, And i was hoping someone with a higher mind than you're truely could help me out a bit.
And before anyone jumps down my throte, I'm not ask for someone to do my homework for me, I'm asking to be tutored abit. How you got the answer, Whats the precedur, That crap. and give me a few examples as well.
Solve For x: 8x - 2 -5x = 8?
adding - 3x2 -5x+1 and 8x2 2x-9
Anyhelp would be apprecaited guys
Last Edited: Jul 12, 2011, 20:34:49
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Tullsy
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Re: A little help
Posted: Jul 12, 2011, 21:19:02
Pretty easy, actually.
In the first one (I'm going to assume you typed it correctly - a polyminal expression of a higher degree would have made it slighty more complicated and require the use of factoring), you want to isolate x. You wrote: 8x - 2 - 5x = 8, let's begin.
First, combine like terms. On the one side, 8x and -5x are like terms - they are multiples of x raised to the same exponent (1). Also on that side is a -2, "move" that to the other side by adding 2 to each side (effectively removing it from one side and placing it on the other). So, from the original, you are left with (without combining the 8x and the 5x) 8x - 5x (or 8x + -5x) and, on the other side, 8 + 2. Combine to get 3x = 10. From there, you're looking for one x, not three, so divide each side by three to get x = 10/3.
Moving on to the second problem: you wanted to know how to add polynomials. It's the same process: collect and add like terms. So, for adding -3x^2 - 5x + 1 and 8x^2 + 2x - 9, you want to first write an expression for the addition: -3x^2 - 5x + 1 + (8x^2 + 2x - 9) (notice the brackets, if it's subtraction this is very important as you have to distribute the negative one through the expression before you subtract it). From there, it becomes -3x^2 + 8x^2 - 5x + 2x + 1 - 9 (I just moved the terms that are similar beside each other to make addition easier...) -3x^2 + 8x^2 = 5x^2, -5x + 2x = -3x, and 1 - 9 = -8, so putting it all together, 5x^2 - 3x - 8.
Any questions?
Edit: math fail.
Last Edited: Jul 12, 2011, 21:42:33
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Xemnas
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Posts: 1987
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Re: A little help
Posted: Jul 13, 2011, 11:45:40
Quote: Pretty easy, actually.
In the first one (I'm going to assume you typed it correctly - a polyminal expression of a higher degree would have made it slighty more complicated and require the use of factoring), you want to isolate x. You wrote: 8x - 2 - 5x = 8, let's begin.
First, combine like terms. On the one side, 8x and -5x are like terms - they are multiples of x raised to the same exponent (1). Also on that side is a -2, "move" that to the other side by adding 2 to each side (effectively removing it from one side and placing it on the other). So, from the original, you are left with (without combining the 8x and the 5x) 8x - 5x (or 8x + -5x) and, on the other side, 8 + 2. Combine to get 3x = 10. From there, you're looking for one x, not three, so divide each side by three to get x = 10/3.
Moving on to the second problem: you wanted to know how to add polynomials. It's the same process: collect and add like terms. So, for adding -3x^2 - 5x + 1 and 8x^2 + 2x - 9, you want to first write an expression for the addition: -3x^2 - 5x + 1 + (8x^2 + 2x - 9) (notice the brackets, if it's subtraction this is very important as you have to distribute the negative one through the expression before you subtract it). From there, it becomes -3x^2 + 8x^2 - 5x + 2x + 1 - 9 (I just moved the terms that are similar beside each other to make addition easier...) -3x^2 + 8x^2 = 5x^2, -5x + 2x = -3x, and 1 - 9 = -8, so putting it all together, 5x^2 - 3x - 8.
Any questions?
Edit: math fail. Can you explain it a bit easier? All this is new to me.
Last Edited: Jul 13, 2011, 11:46:02
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Tullsy
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Posts: 2703
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Re: A little help
Posted: Jul 13, 2011, 15:29:53
Ok, I can try. Let's start with the original expression again (expression is a mathematical sentence containing a set of operations, you know, like addition and subtraction and whatnot): 8x - 2 - 5x = 8. In solving for x, you're looking for a value of x that makes the expression true; that is, the left side and right side are equal. Currently, on the left side, you have multiples of x and a constant (this constant is a non-issue and is easy to deal with): you have eight x's in one term and negative five x's in the other (the term takes on the sign of the operation right before it - ... that's about as simple as I can make that, sorry). Since both of these are multiples of some number (x), you can add them together: 8x + -5x (you do addition, but it's really subtraction because you're adding a negative). Just ignore the x for a moment, it's not really an issue; adding is straight forward: 8 - 5 is what you're doing in simplest form (you can factor out the x, and this is what you're left with, by the way, but it doesn't appear that you have to know that). So, 8 - 5 = 3, but you took out the x, so just put it back in (this isn't _really_ how you do it, but I'm trying to make it simple for you...); 3x is what you're left with from that operation. You still have the two on that side, though. 3x - 2 = 8. Whatever operation is currently being done to the two, do the opposite to both sides (so, in this case you'd add two to each side) leaving you with 3x = 10. Again, you need only one x, not three, so divide each side by three giving you a final answer of x = 10/3.
I have to go, but if that doesn't help you with the second one, I'll come back later and work it out for you. I also took the time to do it on paper, as you'd see it done in an exam, to see if that could help clear things up for you.

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XTR3M3
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Posts: 2602
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Re: A little help
Posted: Jul 14, 2011, 16:29:28
Tullsy, you sound a tad technical. That might be what is confusing him if he doesn't already know the syntax.
Xem, basically the "=" sign is your friend in those types of equations. You use the "=" to get the variable(s) (the x in this case) on one side of the "=" all by itself. Tullsy did a great job explaining it in proper terms, but in simpler terms what you do to one side of the "equals" sign you have to do to the other or it wouldn't be equal anymore. With that in mind, to get rid of the -2 in your first example, you would have to add 2. That gets rid of the -2 and leaves you with 8x-5x on the left side of the equals sign. Now, since it is an "equals" equation, what you do to one side, you have to do to the other....so you add 2 to the right side as well giving you 8+2 or 10. you now have 8x-5x=10. I like to get rid of the easy parts first. Next you subtract the 5x from the 8x leaving you 3x on the left side of the equals. (3x just means "3 x's" or "3 times x"). you now have an equation that looks like this... 3x=10. If 3x means "3 times x", then we would have to divide that side by 3 to get rid of the 3. again, since this is an "equals" type equation, what you do to one side you have to do to the other....so you divide the right side by 3 as well which leaves you with x=10/3 just like Tullsy said.
If this helps you understand, great. if not I tried lol.
Last Edited: Jul 14, 2011, 16:30:13
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Xemnas
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Posts: 1987
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Re: A little help
Posted: Jul 14, 2011, 21:14:00
It's kinda coming back to me a bit, It kinda helped out when you said "you do to one, you do to the other". Brought me back to like 8th grade when my math teacher was teaching us fractions, (yes laugh it up, I didn't learn factions til around that time). Kinda gave me a jolt.
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